x^3-2x^2+5x-10...how do you factor that completely?
2006-09-27 18:22:53 · 5 answers · asked by elisabeta 1 in Education & Reference ➔ Homework Help
You can factor with grouping:
(x^3 + 5x) - (2x^2 + 10)
x(x^2 + 5) - 2(x^2 + 5)
(x-2)(x^2 + 5)
2006-09-27 19:45:30 · answer #1 · answered by greeiore 3 · 0⤊ 0⤋
Using the remainder theorem, we check for any factors.
1 doesn't work so we try 2,(we replace all x's by 2)
2^3 - 2*2^2 + 2*5 -10 = 8 - 8 +10 - 10 =0,
since the value of the expression is zero, that means (x - 2) is a factor of the expression.
dividing the expression by (x-2), we get the quotient as (x^2 +5)
Since this is not factorisable any further, our answer is
(x-2) ( x^2 +5)
2006-09-27 18:37:58 · answer #2 · answered by jazideol 3 · 0⤊ 0⤋
you have to use what is known as synthetic division. You basically divide the polynomial by a monomial so that you can get it simplified and be able to obtain a quadratic equation that can easily be factored...
2006-09-27 18:31:44 · answer #3 · answered by venomfx 4 · 0⤊ 0⤋
(X^2+5) (X-2)
2006-09-27 22:33:03 · answer #4 · answered by ? 5 · 0⤊ 0⤋
seven
2006-09-27 18:24:34 · answer #5 · answered by Gummy 4 · 0⤊ 0⤋