Prove that a^n+b^n=c^n is infinity if a, b,c is integer and n>2?

Question

Prove that a^n+b^n=c^n is infinity if a, b,c is integer and n>2

Answer 1

1^100 + 0^100 = 1^100 !!

note that this is the famous Fermat's Last Theorem... unsolved for centuries... recently proved by Wiles

Answer 2

Divide through n^a on each and each area a million + n^(b - a) = n^(c - a) n^(b - a) + a million = n^(c - a) we are able to component this. (n + a million)(n^(b - a - a million) - n^(b - a - 2) ... ) = n^(c - a) enable n^(b - a - a million) - n^(b - a - 2) ... = S S(n + a million) = n^(c - a) S = n^(c - a) / (n + a million) S must be an integer if a, b, c, n are integers. for the reason that n^(c - a) only has n as an element, n + a million can not be an element. If n + a million isn't an element, S isn't an integer, for this reason a, b, c, n can not be integers. ----- EDIT: as a results of Lobosito's edit, i will edit my answer. n^(b -a) = n^(c - a) - a million we are able to component the RHS and then from branch through n - a million, we instruct that a, b, c, n are not to any extent further integers.

Answer 3

According to Calculus, any number over 11 can be considered infinity. As long as any 2 of the variables (a, b, and c) are greater than 1 this would be true, would it not?

Answer 4

Fermat's last theorem. Proof is too complicated. But it states that if a,b,c are integers then a^n + b^n = c^n is not possible for n>2.
This is what you want, don't you?

Answer 5

Prove it yourself. Then tell me what infinity + 1 equals.

Answer 6

The answer is 42

Answer 7

lol =))