2006-09-27 17:34:03 · 10 answers · asked by Anthony J 1 in Science & Mathematics ➔ Mathematics
3y+5-6(5)+20y-9
=3y+5-30+20y-9
=3y+20y+5-30-9
=24y+5-39
= 24y-34=answer
2006-09-27 18:17:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3y + 5 - 6(5) + 20 y - 9 =0
3y + 5 - 30 + 20y - 9 = 0
3y + 20Y - 39 + 5 = 0
23Y - 34 = 0
23Y - 34 + 34 = 0 + 34
23y = 34
23y/23 = 34/23
y = 34/23
2006-09-28 11:07:22 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
3y + 5 -6*5 + 20y -9 =
3y + 5 - 30 + 20y - 9 =
23y - 39 + 5 =
23y - 34
ANS:23y - 34
2006-09-28 00:41:29 · answer #3 · answered by ssrirag2001 2 · 0⤊ 0⤋
3y+5-6(5)+20Y-9=3y+5-30+20y-9
=23y-25-9
=23y-34
2006-09-28 05:45:06 · answer #4 · answered by srirad 2 · 0⤊ 0⤋
3y+5-6(5)+20y-9=23y-34
2006-09-28 00:38:48 · answer #5 · answered by Vera 3 · 0⤊ 0⤋
3y+5-30+20y-9=
3y-25+20y-9
23y=34
y=34/23
2006-09-28 00:42:44 · answer #6 · answered by caitlinormsby 2 · 0⤊ 0⤋
3Y+5-30+20Y-9
23Y=34
Y=34/23
2006-09-28 00:38:25 · answer #7 · answered by Fred 2 · 0⤊ 0⤋
y=34/23
2006-09-28 00:42:30 · answer #8 · answered by floozy_niki 6 · 0⤊ 0⤋
3y+5-6(5)+20y-9=
(3y+20y)+5-(6.5)-9=
23y+(5-30)-9=
23y+(-25-9)=
23y-34
The answer is= 23y-34
2006-09-28 07:02:17 · answer #9 · answered by J 1 · 0⤊ 0⤋
Do your homework yourself. It's not like algebra takes any real effort.
2006-09-28 00:43:59 · answer #10 · answered by Kharm 6 · 0⤊ 0⤋