correct ur question,
sodium nitride is Na3N
sodium nitrite is NaNO2
which one u want?
Al2(SO4)3 is for aluminium sulfate.
If u want to have only one Al in aluminium sulfate, (AlSO4)+ ion or AlSO4.Cl aluminium chloro sulfate. this is because, aluminium is ready to give 3 electrons in order to become more stable. SO4 can accept 2 electrons. there is one more electron given by aluminium. two assess this, 2 Al atoms give total of 6 electron, and 3 SO4 groups accept a total of 6 electrons.
2006-09-27 21:00:27
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answer #1
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answered by King pandia 2
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No, it should not be AlSO4 because the charge of Aluminum to react is +3 and the charge of the polyatomic anion SO4 is -2. To form the neutral substance, the positive and negative charges must equal. This means you need 2 atoms of +3 Al giving you a total of +6 charges to react with 3 sulfate (SO4 -2 ), or a total of
-6 charges. +6 and -6 gives you zero which is the charge of the whole aluminum sulfate.
2006-10-03 20:09:15
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answer #2
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answered by Aldo 5
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Aluminum is group 3A element. It has +3 charge.
Sulfate ion has -2 charge.
The net charge of the compound must be zero.
(2*(+3))+(3*(-2)) = 0
Sodium nitride's chemical formula is NaNO2
cuper (II) phosphate's chemical formula is Cu3(PO4)2
2006-09-27 17:44:04
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answer #3
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answered by chemboy_bkk 1
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in writing chemical formulas you have to balance charges. Al has +3, SO4 has -2. you have to cross multiply to get the charges to balance. from that you should be able to do the rest yourself
2006-10-02 05:15:02
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answer #4
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answered by shiara_blade 6
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because Al=3 charge and So4 have -2 charge....so the formula is correct!
2006-10-03 16:54:10
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answer #5
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answered by smart-crazy 4
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Al is trivalentm SO4 is divalent so Al2(SO4)3 is correct.
2006-10-04 10:27:46
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answer #6
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answered by yupchagee 7
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ALUMINIUM SULPHATE-YOU ARE RIGHT-
Al2(SO4)3
SODIUM NITRIDE-
NaNO2
COPPER(II) SULPHATE-
Cu3(PO4)2
2006-09-27 18:28:33
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answer #7
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answered by Anonymous
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oh he's right about the first one---AI2(SO4)3
NaNO2; Cu3(PO4)2
2006-09-27 17:31:21
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answer #8
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answered by Jacqueline 2
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