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Complex analysis(under Harmonic Functions)

2006-09-27 17:22:14 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

The Schwartz exists.
Proof: Mel Brooks says so.

Seriously, it's all over my head, but you may find this useful.

http://archive.numdam.org/ARCHIVE/BSMF/BSMF_1989__117_3/BSMF_1989__117_3_319_0/BSMF_1989__117_3_319_0.pdf

2006-09-27 17:40:26 · answer #1 · answered by Helmut 7 · 0 0

Schwarz Theorem

2016-12-15 15:19:05 · answer #2 · answered by ? 4 · 0 0

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