twice as many student tickets as adult tickets were sold. the total reciepts were $1650. how many of each kind of ticket were sold?
2006-09-27 14:59:57 · 6 answers · asked by saira 1 in Science & Mathematics ➔ Mathematics
Let x be the number of adult tickets sold.
Let y be the number of student tickets sold.
Our equations are:
y = 2x
5x + 3y = 1650
Plugging in y=2x into the second equation, we get:
5x + 3*(2x) = 1650
11x = 1650
x = 150
... and since y = 2x, y = 300.
Answer: 150 adult tickets and 300 student tickets were sold.
2006-09-27 15:08:39 · answer #1 · answered by Bramblyspam 7 · 0⤊ 0⤋
300 student tickets and 150 adult tickets. 300 = 150 X 2
300 X $3 + 150 X $5 =
$900 + $750 = $1650
2006-09-27 15:08:08 · answer #2 · answered by wild_turkey_willie 5 · 0⤊ 0⤋
If s represents the number of student tickets, we can write
3s + 5s/2 = 1650
6s + 5s = 3300
11s = 3300
s = 300
so the number of adult tickets is half that, or 150.
Check: 3(300) + 5(150) = 900 + 750 = 1650
2006-09-27 15:07:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
adult ticket = x, student ticket = y, twice students' r sold,
2x = y (i)
adult ticket = $5, student ticket = $3, total = $1650,
5x + 3y = 1650 (ii).
(i and ii)
5x + 3(2x) = 1650,
11x = 1650,
x=150.
(i)
2(150)=y,
y=300.
so there are 150 adult tic and 300 student tic.
2006-09-27 15:12:01 · answer #4 · answered by harri s 3 · 0⤊ 0⤋
Great point, I'd like to know more as well
2016-07-27 13:06:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋
very interesting question
2016-08-23 07:44:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋