Okay I got a really good answer on my last question, but how would you solve the angle of a triangle if all you knew where the sides and that it is a 90 degree triangle.
I know sin, tan, or cos, but am blanking pls help!!
2006-09-27 14:43:21 · 3 answers · asked by Justin 4 in Science & Mathematics ➔ Mathematics
Well if you know the sides and the fact that it is a 90° angle, you can use
SOH CAH TOA to get your answer.
Sine θ = opposite / hypotenuse
Cosine θ = adjacent / hypotenuse
Tangent θ = opposite / adjacent
Pick an angle to start out with. If you use sine, you will divide the length of the side opposite that angle by the hypotenuse, and take the inverse sine. That will give you the angle.
Once you have the angle, you can subtract the values from 180° (number of degrees in a triange) to find the remaining angle.
2006-09-27 14:48:46 · answer #1 · answered by Kayla 3 · 1⤊ 0⤋
Okay, you have tables right? If the triangle has sides O,A,H such that side O is the opposite side, side A is the adjacent side and side H is the hypotenuse. then one angle has the cosine = A/H and the other has the sine = O/H ....got it?
2006-09-27 21:55:57 · answer #2 · answered by eantaelor 4 · 0⤊ 1⤋
sin(x) = opposite/hypothenuse
cos(x) = adjacent/hypothenuse
tan(x) = opposite/adjacent
http://www.math.com/tables/trig/identities.htm
2006-09-27 21:50:54 · answer #3 · answered by Sherman81 6 · 0⤊ 1⤋