Please provide the factoring of this problem by using the quadratic equation and the the way when your use this (x )(x ). Explain step by step both of the ways and earn 10 points immediately.
2006-09-27 14:07:21 · 4 answers · asked by BENNETH[[98]] 2 in Science & Mathematics ➔ Mathematics
Find the value for x
2006-09-27 14:51:01 · update #1
Assuming you mean 6x^2+19x+7=0
This equation is not factorable. The only way to get 7 is 1 x 7. The factors of 6 are 1*6 and 2*3, so here are the possible combinations:
(x+1)(6x+7) This gives you 6x^2+13x+7
(x+7)(6x+1) This gives you 6x^2+43x+7
(2x+1)(3x+7) This gives you 6x^2+17x+7
(2x+7)(3x+1) This gives you 6x^2+23x+7
(3x+1)(2x+7) This gives you 6x^2+23x+7
(3x+7)(2x+1) This gives you 6x^2+17x + 7
2006-09-27 14:23:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I somehow believe you've boo booed your equation. Why would you have two terms with nothing but numbers, no variables.
What you gave is 6x^2 + 26 = 0?
To factor reduce the equation to x^2 = -26/6 and solve for x. Note you have a negative sign; so your answer will be imaginary rather than real. Which is one reason I think you boo booed.
2006-09-27 21:26:52 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
6x^2 + 19x + 7
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-19 ± sqrt(19^2 - 4(6)(7)))/(2(6))
x = (-19 ± sqrt(361 - 168))/12
x = (-19 ± sqrt(193))/12
x = (1/12)(-19 ± sqrt(193))
assuming you meant 6x^2 + 19x + 7, then this problem can't be factored.
2006-09-27 21:42:47 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
take 6 x 2 add 19 and then add 7
answer 44
2006-09-27 21:10:22 · answer #4 · answered by sean f 1 · 0⤊ 0⤋