estimate the coefficient of static friction for a drag racer that covers the quarter mile in 6.0 s?

Question

drag race tires in contact with an asphalt surface probably have one of the highest coefficients of static friction in the everyday world

this is for ap physics

drag race tires in contact with an asphalt surface probably have one of the highest coefficients of static friction in the everyday world

include the gravity which is 9.8N

Answer 1

At equilibrium, frictional force = kinetic force
w*f=m*a
m*g*f=m*a
g*f=a
f=a/g, where f is friction constant, w is weight of racer, m is mass of racer, g is gravitational acc. and a is racer acc.
But, S= 0.5*a*t^2, where s is distance covered and t is time elapsed. Thus,
a=2*S/t^2
a=2*0.25miles*1600m/mile/6^2
a=22.2 meters/s^2
Therefore,
f=22.2/9.81
f=2.26 (!)
( I think f<=1in reality, which in this case shows the assumtions in the question have to be refined for practical purposes)

Answer 2

In the absence of further information, assume uniform acceleration. Then you can find the acceleration from d=a*t^2/2. The minimum effective coefficient of friction is the ratio of the car's acceleration to the acceleration of gravity pushing down on the car. I say effective coefficient because there are other forces involved besides gravity - aerodynamics, e.g.

I'll let you turn the crank, but I think you'll find the answer is greater than 1.

Answer 3

not enough information.
What is the force on the car?
What is the mass of the car?