-[-(3x-5)-x]
X= -9
its algebra
2006-09-27 13:30:46 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i got -41 but my mom got -23 somehow
who is right??
2006-09-27 13:36:32 · update #1
this is what i did
-[-(3x-5)-x
=-[-(3*(-9)-5)-(-9)
=-[-(27-5)-(-9)
=-32-(-9)
=-41
2006-09-27 13:42:58 · update #2
Put a -9 in place of every x, then start adding/multiplying from inside parenthesis out. First do (3x-5) which is -27-5 or -32. This is preceded by a - sign so the result from the curved parethesis is 32. The next parenthesis is the square brackets which now contains [32 - x] or [32 - (-9)] or [[32+9] or [41]. Finally multiply by the - in front to get -41
2006-09-27 13:42:12 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
-[-(3x-5)-x with x = -9
-[-3x+5--9]
-[-3x+5+9]
3(-9)-5-9
-27-14
-41
2006-09-27 13:35:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1st -9*3 = -27
2nd -27 -5 = -32
3rd -32 -(-9) = -32 +9 = -23
4th -(-23) = 23
2006-09-27 13:44:49 · answer #3 · answered by rfleclerc 2 · 0⤊ 0⤋
I got -41.
2006-09-27 13:41:50 · answer #4 · answered by heinlein 4 · 0⤊ 0⤋
-[-(3(-9)-5)--9]
-[-(-27-5)+9]
-[27+5+9]
-[41]
=-41
2006-09-27 13:46:36 · answer #5 · answered by Ram 2 · 0⤊ 0⤋
I believe the answer is {-41}. see if you get that.
2006-09-27 13:39:20 · answer #6 · answered by williams_synithia 1 · 0⤊ 0⤋
-[-(3x-5)-x]
3x-5+x
4x-5
for x=-9
4(-9)-5
-36-5
-41
2006-09-27 13:46:54 · answer #7 · answered by Anonymous · 0⤊ 0⤋
should be -24.
2006-09-27 13:36:17 · answer #8 · answered by Anonymous · 0⤊ 0⤋
-[-(3x-5)-x] and x= -9
-[-(3x-5)-x]
=-[x(3x-5x)]
=-[3x^2-5x)]
=-3x^2+5x
=-3(108)+45
=-324+45
=- 279
2006-09-28 23:02:42 · answer #9 · answered by ticia 1 · 0⤊ 0⤋
-21x=-23
2006-09-27 13:40:16 · answer #10 · answered by Anonymous · 0⤊ 0⤋