15,000,000,000 =
0.0000000250=
2006-09-27 12:55:53 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
It looks like 2 and 3.
It's a bit tricky with the 15,000,000,000 though, there is no way to tell if it's bean rounded off to 2 or more significant digits.
2006-09-27 13:00:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋
11 and 3
2006-09-27 12:57:07 · answer #2 · answered by Brian 3 · 0⤊ 1⤋
the first one has 10, the reason being that when your counting sig figs, the last zero in number, to the right of the decimal can be considered uncertain, becuase it is undefined. (no way to tell if it is rounded to 2 or more sig figs). Depending on how the number is displayed, if its a definition (1m=1000m, where 1000 would have 4 sig figs) you d count them all, if not then then number could just be counted as "uncertain." The second one has 3 sig figs.
http://www.sciencebyjones.com/sig_figs.htm
2006-09-27 13:02:32 · answer #3 · answered by k soni 2 · 0⤊ 1⤋
actually, the first one has 2-11 significant figures, and the second has 3.
2006-09-27 15:31:31 · answer #4 · answered by frogster99 2 · 0⤊ 0⤋
1st one 2...trailing zeroes are not signifcant without a decimal point
2nd one 3... place holder zeroes are not significant, trailing zeroes with a decimal point are significant
2006-09-27 13:10:16 · answer #5 · answered by The Cheminator 5 · 0⤊ 0⤋
dimension 43.00, .175, .250, .50.......do the .xx .001 is this a tolerance of +-, and how is the .xx related to this??
2006-09-27 13:01:41 · answer #6 · answered by larry b 1 · 0⤊ 1⤋