The largest of the pyramids of Egypt has a square base with sides 755 feet long. Angle PQR has a measure of 52 degrees. The top of the pyramid is no longer there. What was the pyramids original height (RP) to the nearest foot?
There is also a drawing of a pyramid that shows that angle Q is 52 degrees, and angle R is 90 degrees, and that each side is 755 feet. The tip of the pyramid is angle P, which I assume is 38 degrees. Can someone please help me with this? Thanks so much.
2006-09-27 12:28:00 · 2 answers · asked by kay 1 in Education & Reference ➔ Homework Help
Since you know all the bases are 755 ft. long. Then you divide 755 by two becasue then you will get half the length which results into one side of the triangle PQR. So half the length is 377.5. Once you get that you can use tangent of angle Q. Since the angle of angle q is 52 degrees then all you do is tangent 52 degrees=face to / next to. So it is tangent 52 degrees= x/377.5. X is the height. Then you figure out what tangent 52 degrees is. After that, you times 377.5 and then you get the height of the pyramid. This is guidance on how to do it. You calculate the final answer because i don't want to get a scientific calculator right now.
2006-09-27 12:37:58 · answer #1 · answered by silentcargo 3 · 0⤊ 0⤋
You are correct.
The pyramid side can be modeled as a triangle, and then apply simple trigonometry.
The 755/2 feet is the base of a right triangle.
Since you know one angle and the base, you can find the height as Tangent 52=height/(755/2)
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2006-09-27 12:33:03 · answer #2 · answered by odu83 7 · 0⤊ 0⤋