I have been working for hours and i don't understand what am i doing wrong. The orginal equation is Cl2 -----> Cl-1 OCl-1. The -1 are the charges. I need someone to explain and go through the steps to solve this equation
2006-09-27 11:51:49 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
In Cl-, chlorine has oxidation state -1
In OCl-, chlorine has oxidation state +1 (since overall oxidation state is -1 and in all cases O has oxidation state -2, except the compounds with fluorine and peroxydes)
so, molecular chlorine, Cl2, with oxidation state 0 changes (disproportionates) to compounds with oxidation state +1 and oxidation state -1 :
Cl2º + 2*HO- ---> Cl- + OCl- + H2O
2006-09-28 13:46:08 · answer #1 · answered by andreicnx 3 · 0⤊ 0⤋
Cl2 Cl Ocl
2017-01-19 13:47:16 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Cl2-------Cl-1+Cl-1..............cant happen! Now Cl2+2e--------Cl-1+Cl-1 can happen. Now the charges on both sides of the equation are balanced, left side = -2, and right side = -2.
2006-09-27 11:58:57 · answer #3 · answered by cyberpat1957 1 · 0⤊ 1⤋
This reaction occurs when you dissolve chlorine in dilute and cold alkaline solution:
Cl2 + 2KOH -> KCl + KOCl + H2O
So, in ionic form we have:
Cl2 + 2OH- -> Cl- + OCl- + H2O
2006-09-27 12:03:29 · answer #4 · answered by Dimos F 4 · 0⤊ 1⤋