2006-09-27 10:31:46 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x*(x^3-12x^2+48x-64)
=x*(x^3+3*(-4)*x^2
+3*(-4)^2*x+(-4)^3)
=x*(x-4)^3
2006-09-29 21:28:27 · answer #1 · answered by Mamad 3 · 0⤊ 0⤋
Factor an x out:
x(x^3 - 12x^2 + 48x - 64)
The second polynomial doesn't factor by traditional methods, so you know that the possible roots are the factors of the constant term divided by the factors of the highest polynomial:
Possible roots are x=+/-1,2,4,8,16,32, 64
Using long division (or synthetic division or substitution), you can discover the other roots (besides x=0 obviously).
2006-09-27 19:28:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I guess you mean simplify the expression.
Factoring will be the KEY method!
x (x - 4)^3 is the factored answer...
2006-09-27 10:42:41 · answer #3 · answered by Isaac 2 · 0⤊ 0⤋