solve for variable?

Question

equation: s= -16x^2 +100x

how do i solve for "t"?

would "t" = 25 +/- (sqrt 625-4x) / 2

"t" = "x" sorry.

Answer 1

well dear first hi;
if f(x) = ax^2 + bx + c
∆ = b^2 - 4ac
x1 = (-b + √∆) / 2a
x2 = (-b - √∆) / 2a
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now here;
if s = -16x^2 +100x
a = -16 , b = +100 & c = 0
∆ = b^2 - 4ac = (100)^2 - 4(-16)(0) = 10000 -0 = 10000
∆ = 10000

x1 = (-b + √∆) / 2a = (-( 100) + √10000)) / 2(-16) =
-100 + 100 / -32 = 0/ -32 = 0
x1 = 0

x2 = (-b + √∆) / 2a = (-( 100) - √10000)) / 2(-16) = -200/ -32 =
x 2 = +6.25

Good Luck dear.

Answer 2

So you need to solve for x in terms of s?
Move everything to the left side.
16x^2 - 100x + s = 0
Now use the quadratic formula
a = 16, b = -100 and c = s

Answer 3

Fortunately, this one IS quadratic. So, you can tediously move every thing over and solve for "x" or you can use the quadratic formula and let c = -s