i need help with this question...maybe a formula or something..please?
A helicopter is ascending vertically with a speed of 7.00 m/s. At a height of 195 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground? [Hint: The package's initial speed equals the helicopter's.]
2006-09-27 09:01:07 · 4 answers · asked by arae 2 in Education & Reference ➔ Homework Help
Use the distance formula:
d = vit + 1/2at^2
d = 195m
vi = 7.0 m/s
a = -9.8 m/s^2 (since it's going down)
That should give you enough to solve for t.
2006-09-27 09:09:11 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
If I remember high school physics, an objects falls to earth at 9.8 m/s. So, if a package was dropped from a height of 195m, it would take 19.89 seconds before it hits the ground (195 / 9.8 = 19.89). This is assuming gravity is constant and there exists no drag (such as wind). Let me know if I am right on this. Thanks!
2006-09-27 09:14:16 · answer #2 · answered by California_Cruisin' 3 · 0⤊ 0⤋
if speed=distance/time
then time must be,
time=distance/speed
time=195/7
time=27.8571
time=27.9seconds
we were doing this stuff in physics on monday, so i think that's it. hope it helps :D
2006-09-27 09:10:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
multiply 7.00 and 195; you should get....
1365
2006-09-27 09:12:45 · answer #4 · answered by Lil Princess 1 · 0⤊ 0⤋