W= (2PR) / R-r solve for R?

Answer 1

don't be lazy! and if you not then listen so you can learn
solve for R, we want this to be by itself
make sure the problem reads like: W =(2PR)/R - r and not W=(2PR)/(R-r)

Since you have W = (2PR)/R - r the numerator R and demoninator R cancel out

leaving W = (2P) - r which doesn't make sense with what you're asking

if the problem reads like W =(2PR)/(R - r )
then
move denominator over to W
W(R - r) = 2PR and distribute W
WR - Wr = 2PR and move 2PR over
WR -Wr - 2PR = 0 and move Wr over
WR - 2PR = Wr and Facotr out R
R(W - 2P) = Wr and div by ()
R = Wr/(W - 2P)
and there you have it.

Answer 2

The way you have this set up it does not matter what R is because it cancels out anyway (can not equal zero).

Answer 3

W = 2PR/R-r

W(R-r) = 2PR

2PR = W(R- r)

2PR = WR - Wr

2PR - WR = -Wr

R(2P - W) = -Wr

R = -Wr/(2P-W)

Answer 4

Yes, Frank is correct.

R = -Wr/2P-W

Answer 5

2x pi moses times the greatness of water splitting plus poor peoples sadness and there soles= ME!!!!!!!! moses

Answer 6

R= W/ 2P........If thats what your question...or it could be
R= -W/2P............I think you need to re-enter the question so we can see exactly what your asking..........