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Please help!
I need to know how to simplify this problem and others like this problem.

25-[10a-(11b-7)-(16b-14)+(8b+6-3)]

2006-09-27 07:44:27 · 5 answers · asked by Anonymous in Education & Reference Homework Help

5 answers

Remember order of operations:
1.) Do everything in the parenthesis first.
2.) Do exponents/logarithms (doesn't seem to apply here)
3.) Do multiplication/division
4.) Do addition/subtraction

Once you've done that, simplify by combining like terms:
For example: 12a + 1b + 15a + 3 + 13a - 2b can be rewritten as:
12a + 15a + 13a + 1b - 2b + 3
40a - 1b + 3

that's as far as that can be simplified.

2006-09-27 07:54:27 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

You need to re-enter it so the whole problem shows up. But basically if there's a minus sign outside parentheses, change it to plus and change the sign of each thing inside the parentheses. Then add every like term inside the brackets. Then multiply everything by the number outside the brackets.

2006-09-27 14:49:33 · answer #2 · answered by hayharbr 7 · 0 0

Previous posts are correct, we cannot help until the whole problem is posted. Study "order of operations" on the net. Briefly, inside the parentheses is done before outside, then add and subtract before you multiply and divide.

2006-09-27 14:53:52 · answer #3 · answered by Anonymous · 0 0

25-[10a-(11b-7)-(16b-14)+(8b+6-3)]
=25-(10a-11b+7-16b+14+8b+3)
=25-(10a-27b+24+8b)
=25-(10a-19b+24)
=1-10a+19b

2006-09-27 15:10:16 · answer #4 · answered by ioana v 3 · 0 1

its not all there !

2006-09-27 14:48:27 · answer #5 · answered by Anonymous · 0 0

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