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f (x) = 7x^4-8x^3-5

2006-09-27 07:13:45 · 4 answers · asked by Girl 5 in Science & Mathematics Mathematics

4 answers

f'(x)=28x^3-24x^2

2006-09-27 07:23:47 · answer #1 · answered by Anonymous · 1 0

f(x) = 7x^4 - 8x^3 - 5
f'(x) = (7 * 4)x^(4 - 1) - (8 * 3)x^(3 - 1)
f'(x) = 28x^3 - 24x^2

2006-09-27 14:00:36 · answer #2 · answered by Sherman81 6 · 1 0

f(x) = 7x^4 - 8x^3 - 5
f'(x) = 28x ^3 - 24x^2
QED

2006-09-27 08:10:50 · answer #3 · answered by CSUFGrad2006 5 · 1 0

f'(x) = 28x^3-24x^2
f''(x) = 84x^2-48x
f'''(x) = 168x-48
f''''(x) = 168
f'''''(x) = 0

2006-09-27 07:16:58 · answer #4 · answered by AresIV 4 · 1 2

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