y= ???
2006-09-27 06:08:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
dy/dx= (1+x^2-2x^2)/(1+x^2)^2
= (1-9)/(100)
= -0.08
y-0.3=-.08(x-3)
y+0.08x=0.06
2006-09-27 06:17:43 · answer #1 · answered by Gunjit M 2 · 0⤊ 0⤋
I'll give you a bit of hint. The slope of the tangent line to a curve at any point of it, is equal to the value of the curve function's differentiation with respect to x. Calculate that in the desired point. Then, having the slope of the line and one of the points it passes through (which is the point on the curve), you can derive the line equation.
2006-09-27 13:19:41 · answer #2 · answered by Mahyar 3 · 0⤊ 0⤋
differenciate to find slope equation...
2006-09-27 13:14:14 · answer #3 · answered by ashwin_hariharan 3 · 0⤊ 0⤋
0.3
2006-09-27 13:11:05 · answer #4 · answered by Teacher 4 · 0⤊ 0⤋