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Calculate the force of gravity between the earth(mass=6*10^24kg) and the sun (mass=2*10^30kg, distance 1.5*10^11m)

My work thus far:

. F= G (m1+m2)/d^2

F= (6*10^24) (2*10^30)/ (1.5*10^11) ^2

how do I figure out 10^24...10^30.....10^11 etc...and do I need to complete it to that extent?

2006-09-27 04:40:03 · 4 answers · asked by wildbutterflychick 2 in Science & Mathematics Physics

4 answers

G=6.6742*10^-11 Nm^2 kg^-2
Ms=2*10^30 kg
Me=6*10^24 kg
d=1.5*10^11 m
Force in N
=(6.6742*10^-11)(2*10^30)(6*10^24)
/1.5*10^11
=6.6742*8(10^-11*10^30*10^24/10^11)
Now we have to be clear about the law of indices
which are as under.
a^x*a^y=a^x+y
aX/a^y=a^x-y
a^x^y=a^xy
these are three laws out of which first two apply.
All you need to do is to add indices when multiplying and subtract indices when dividing.
We therefore have
force in N=53.37*10^21

2006-09-27 05:47:58 · answer #1 · answered by openpsychy 6 · 1 0

Actually
F = G*m1*m2/d^2
and G = 6*10^-11

so, F = 6*10^-11 * 6*10^24 * 6* 10 30/(1.5 * 10^11)^2

SO AFTER CALCULATION F = 4*10^21

2006-09-27 04:54:02 · answer #2 · answered by ssrirag2001 2 · 1 0

If you are correct with the calculations,

I think it's -24 instead of 24.

Then put - 24 + 30 - 11 * 2

In my country, you do need to complete it to a further extent.

2006-09-27 04:44:00 · answer #3 · answered by S2ndreal 4 · 1 0

10^24 means 10 to the power of 24.. meaning 10x10x10... for 24 times.. it would definitely be easier if u're using a scientific calculator.. press 10 EXP 24 (EXP stands for exponential power).. all else, be very careful when u plus both the masses of the earth and the sun

2006-09-27 04:50:07 · answer #4 · answered by I need a vacation! 4 · 1 0

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