Okay, I have some serious issues with quantum numbers! heres an example of one of my problems:
Draw an orbital diagram for Sulfur (this i can do) then give a full set of quantum numbers for the last electron in the 3rd energy level of the sulfur atom. so i know n=3 (3rd) and that s= negative 1/2 how do i know what l and m equal exactly (and not just l=0 to (n-1) and m is -l to +l?)
2006-09-27 04:24:17 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help
okay dont give me this! dont be a *****! for god sakes this stuff is REALLY hard and we have a LARGE class so getting all of ur answers in is hard. plus this has been a stressful week and i have not been able to come in early. dont tell me that u have NEVER had a test that u really didnt get to study much on. so right NOW i need HELP and NOT lecturing. Thank you very much!
2006-09-27 04:29:10 · update #1
annnnd i DID study last night for 2 hours! so give me a break!!!! we just went over this stuff YESTERDAY for the first time, so i apologize that im confused Raquel.
2006-09-27 04:31:52 · update #2
configurationn is 1s2 2s2 2p6 3s2 3p4
2006-09-27 04:43:15 · update #3
OK:
Sulphur's 3rd level can be stated as 3s2 3p4. You're looking at the 4th election in 3p.
n = 3, like you noted (same shell)
l is related to the subshell: s,p,d,f,g relate to 0,1,2,3,4. Since our election is in the p subshell, l = 1.
m is based on the atomic orbital. The final electron is in the highest energy state. m as 3 possible states: -1, 0, 1, each of which may hold 2 elections. The first 2 3p electrons are in the -1 state, so the last 2 3p electrons are in the 0 state.
Thus:
n = 3, l = 1, m = 0, p = -1/2
2006-09-27 05:10:40 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
You should have been studying all along. Why did you wait until the day of the test to realise that you need help in this area?
2006-09-27 04:27:10 · answer #2 · answered by RACQUEL 7 · 0⤊ 3⤋