Hi, to solve this question, we have 2 equations:
Let a = first number
and b= second number
(1) a x b= 360
(2) a+b = 77
Now, it is a matter of solving simultaneous equations.
Ill show you a solution by substitution method,
from (2) we can get b=77-a
substitute this equation to (1)
(1) becomes
a x (77-a) = 360
77a - a^2 = 360
which gives -(a-72)(a-5)=0
so a= 72 and b = 5
cheers!
2006-09-27 02:03:12
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answer #1
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answered by 123456 1
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I assume you mean, "What are two factors of 360 that have a sum of 77?", because 77 is not a factor of 360, and thus there is no "factor of 360 that equal 77." You need to set up a quadratic equation. If one factor is x, the other factor has to be (77 - x) for the two factors to sum to 77. Then x(77 - x) = 360. Multiply it out and rewrite it as x^2 - 77x + 360 = 0. Now use the quadratic formula. [77 +/- sqrt(77^2 - 4*360)]/2 = 72 and 5. As you can see, 72 + 5 = 77 and 72*5 = 360.
2006-09-27 01:36:53
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answer #2
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answered by DavidK93 7
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The prime factors of 360 = 2*2*2*3*3*5
If u wanna write only two factors then u can write as follows:
2*180 = 360
or 4*90 = 360
or 8*45 = 360
or 24*15 = 360
or 72*5 = 360
or 1*360 = 360 (of course :-) )
2006-09-27 01:55:27
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answer #3
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answered by reu_999 2
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72 and 5 are two factors of 360.And if u add both means 72+5=77.
2006-09-27 01:45:56
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answer #4
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answered by coolcollegian.dhams 1
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Since 350 factors completely into 2*2*2*3*3*5 it's pretty simple to see (by inspection) that 72 and 5 are the numbers you're looking for âº
Doug
2006-09-27 01:40:10
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answer #5
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answered by doug_donaghue 7
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72 and 5
2006-09-27 01:44:16
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answer #6
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answered by Coolguy_punjabi 3
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5 and 72. Considering you to be a lot more intelligent and educated,tell what's the CATCH?
2006-09-27 01:40:38
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answer #7
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answered by brkshandilya 7
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2*2*2*3*3*5=360
2*2*2*3*3=42
77=42+5
2006-09-27 02:29:00
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answer #8
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answered by Patricia Lidia 3
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180 and 180 may be!!!
2006-09-27 01:41:23
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answer #9
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answered by bella 2
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there isn't one
2006-09-27 01:41:26
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answer #10
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answered by Sueeee....... 2
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