What is 19 over 4 take 3? (algebra) the whole question is 4a+3=19, solve it?

Question

and how would you do it cuz of the fraction

Answer 1

minus 3 from both sides
divid both sides by 4

Answer 2

we subtract 3 from each side of the equation and get 4a =16 next,we divide by 4 and find that a=4
4a + 3 = 19
if a is 4
4 x 4 = 16 +3 19

Answer 3

The other answerers are right: when solving this equation, you should subtract 3 from both sides first, giving 4a = 16. *Then*, when you divide both sides by 4, you get a = 4.

However, you can divide by the 4 first if you want -- *as long as* you divide the entirety of each side by 4! That means that, on the left side, you divide both terms by 4, giving:

a + 3/4 = 19/4.

Then, when you subtract the 3/4 from both sides, you get

a = 19/4 - 3/4 = 16/4 = 4, which is the same answer we got doing it the other way.

As a general strategy: when you're solving an equation, you sort of work the order of operations *backwards.* The expression on the left side of the equation reads "4a+3," and the order of ops tells us that if we knew what a was, we would multiply it by 4 first, then add 3. When we solve for a, we undo those steps, last to first.

Hope that helps!

Answer 4

4a+3=19
=> 4a=19-3
=> 4a=16
=>a=16/4
=> a=4. answer

Answer 5

it's not 19 over 4 take three. it's 19 minus 3 all over four.

4a+3 = 19

add -3 both sides (addition property of equality)

4a+3-3 = 19-3
4a = 16

multiply both sides by 1/4 (multiplication property of equality)

a=4

Answer 6

4a+3=19 --> a=4.

Answer 7

4a+3=19
4a=19-3
4a=16
4a/4=16/4
a=4

Answer 8

4a + 3 = 19
4a = 16 (subtract 3 from both sides)
a = 4 (divide both sides by 4 to get a on it's own)

a = 4

Answer 9

You subtract 3 from each side and get 4a=16. Divide both sides by four and you get a=4.

Answer 10

4a+3=19
4a+3-3=19-3
4a=16
a=16/4
a=4

Answer 11

4a+3=19
4a=19-3
4a=16
a=16/4
a=4