I need one equation for 3 different ses of numbers, and i need this in bout two or three hours maximum!! plz help!!!
the numbers are:
1. 12, 20, 28, 36, 37, 38
2. 13, 22, 31, 40, 4, 42
3. 17, 27, 37, 47, 48, 49
Thx if u actually try do dis!!!! but plz i truely need dis!!
Thx in advance
2006-09-26 22:10:12 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Assuming that the 5th number in 2. is really 41, and allowing discontinuous functions:
1. y=12+8*(n-1), n{1,2,3,4}, y=36+(n-4), n{4,5,6)
2. y=13+9*(n-1), n{1,2,3,4}, y=40+(n-4), n{4,5,6)
3. y=17+10*(n-1), n{1,2,3,4}, y=47+(n-4), n{4,5,6)
For continuous functions, use the brute force method below.:
y=a+bx+cx^2+dx^3+ex^4+fx^5
1.
a+b+c+d+e+f=12
a+2b+4c+8d+16e+32f=20
a+3b+9c+27d+81e+243f=28
a+4b+16c+64d+256e+1024f=36
a+5b+25c+125d+625e+3125f=37
a+6b+36c+216d+1296e+7776f=38
2.
a+b+c+d+e+f=13
a+2b+4c+8d+16e+32f=22
a+3b+9c+27d+81e+243f=31
a+4b+16c+64d+256e+1024f=40
a+5b+25c+125d+625e+3125f=4
a+6b+36c+216d+1296e+7776f=42
3.
a+b+c+d+e+f=17
a+2b+4c+8d+16e+32f=27
a+3b+9c+27d+81e+243f=37
a+4b+16c+64d+256e+1024f=47
a+5b+25c+125d+625e+3125f=48
a+6b+36c+216d+1296e+7776f=49
2006-09-26 22:48:17 · answer #1 · answered by Helmut 7 · 1⤊ 2⤋
I'm not really sure what you are asking for here. If you are asking for an equation to determine what the next series of numbers would be based on a pattern, I have to make an assumption that the second line should have been this.
2. 13, 22, 31, 40, 41, 42
If I am correct, then your equation for the next series of numbers starting with a given number represented by x would be:
4. x, (x+11), (x+22), (x+33), (x+34), (x+35)
Good Luck
2006-09-26 22:44:41 · answer #2 · answered by Bird 2 · 0⤊ 0⤋
Give Helmut the 10 points!
2006-09-27 00:16:09 · answer #3 · answered by ioana v 3 · 0⤊ 0⤋
Hi dear ,
I think this function could help you , good luck
f(n)= 4.(2n+1) + (n-1).(n-2).(n-3).(n-4).(-7/24) + (n-1).(n-2).(n-3).(n-4).(n-5).(21/120)
2006-09-26 23:09:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Are you kidding and trying to make people slog for no reason and you have some fun!!! Am sorry!!
To really try and solve, first check your question, especially your second set of numbers and confirm if they are in order!!!
Please avoid trying fast ones on others!!!!
All others please note!!
2006-09-26 22:44:59 · answer #5 · answered by Manindomb 2 · 0⤊ 1⤋
This is really difficult....
I can get you 3 eq.. but you want only 1 eq. !!!
2006-09-26 22:20:23 · answer #6 · answered by jmdanial 4 · 0⤊ 0⤋