2006-09-26 17:45:43 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
the factors are 17 and -7
2x^2+3x-119
2x^2-14x+17x-119
2x(x-7)+17(x-7)
(2x+17)(x-7)
2006-09-26 17:58:59 · answer #1 · answered by beddazzled_devil 2 · 0⤊ 0⤋
I'm assuming you mean 2(x squared)+3x-119
The key is getting all your factors lined up correctly.
2(x squared)+3x-119=0
The key to solving this equation is the number 119,
and+ 3x. You need to factor out 119, so two numbers
that are multiplied together can solve this. I put 17 with
x, because it is larger than 7 and we know the number
in front of x is greater than 0.
(2x +17 )(x- 7)=0
This means a solution set of (2x+17) and (x-7)=0
x= -17/2 and x=7. The solution is {-8.5,7}.
I'm not sure about the notation, but I know those are
the only two numbers that will fulfill the requirements for
the solution. I hope you can understand the solution, which
are the steps to get to the answer, not just the answer itself.
If you just copy down the answer, without learning the steps
to get there you're screwed.
2006-09-27 00:56:15 · answer #2 · answered by Answerer17 6 · 0⤊ 0⤋
2x^2 +3x -119 =0
multiply 2 and 119 = 238which factorises as 17 * 14.
2x^ 2 +17x -14x -119 =0
2x^2 -14x +17x -119 =0
2x ( x-7 ) + 17(x -7 )=0
2x +17 ) (x -7) =0
x= -17/2 or x= 7
2006-09-27 05:09:34 · answer #3 · answered by macline k 2 · 0⤊ 0⤋
2x^2-14x+17x-119 (break down the middle term)
2x(x-7)+17(x-7) (factor by grouping)
(2x+17)(x-7) (factors)
2006-09-27 00:57:42 · answer #4 · answered by Deana G 5 · 0⤊ 0⤋
2X^2 = 2X * X
119 = 7*17
So we can write the above in the form of
(2X +17) * (X-7)
Hope this helps
2006-09-27 00:55:48 · answer #5 · answered by boyjackie 2 · 0⤊ 0⤋
(2x^2+17)(x^2-7)
2006-09-27 00:54:12 · answer #6 · answered by davidkwankwokfai 3 · 0⤊ 1⤋
Try: (2X + 17) (X-7)
2006-09-27 00:56:46 · answer #7 · answered by jbtascam 5 · 0⤊ 0⤋
(2x+17)(x-7)
2006-09-27 00:54:44 · answer #8 · answered by Dana Renee 2 · 0⤊ 0⤋