the sum of two numbers is 58. The second is 4 more than 2 times the first. What are the two numbers?
2006-09-26 17:12:55 · 4 answers · asked by ♠ melisa ♠ 2 in Education & Reference ➔ Homework Help
x =smaller number
2x+4 = larger number
x + 2x+4= 58
3x+4 =58
3x= 54
x =18 smaller number
2x+4 = 40 larger number
hope this helps
2006-09-26 17:17:29 · answer #1 · answered by bizime 7 · 0⤊ 1⤋
x+y=58
y=4+2x
Subtract second equation from first equation.
x+y-y=58-(4+2x)
x=58-4-2x
3x=54 (added 2x to both sides and did a subtraction)
x=54/3=18
x+y=58 so
18+y=58
y=40
Check to see if these numbers work in other equation:
y=4+2x
40=4+2*18?
40=4+36?
40=40? check
The first is 18 and the second is 40.
2006-09-26 17:21:21 · answer #2 · answered by Robert B 5 · 0⤊ 1⤋
a+(4+2a) = 58
a+4+2a = 58
4+3a = 58
3a =58-4
3a = 54
a = 18 and
(4+2a)
[4+ 2(18)]
4+ 36
40
18 and 40!
2006-09-26 17:31:22 · answer #3 · answered by californian 2 · 0⤊ 1⤋
27 and 31
2006-09-26 17:16:13 · answer #4 · answered by Anonymous · 0⤊ 2⤋