I'm given two equations, and I'm trying to solve for T1 and T2. Here is the first equation:
-T1cos40+T2cos40=0
The second equation:
T1sin40+T2sin40-100=0
I know I need to solve for one of the T's, then put it back into the other equation. But I'm completely stuck. I know my answer is supposed to be 77.8 N (T1=T2) based on my teacher's answer. All she did was work it out to that point, and I'm supposed to know how to solve it. But I don't. So, please help if you can!!
2006-09-26 17:07:45 · 3 answers · asked by MegW12 4 in Education & Reference ➔ Homework Help
easy way:
in equation 1,
T2 cos40 = T1cos40
divide both sides by cos40,
therefore T1=T2.
then quantify T1 (or T2) in the second equation.
2006-09-26 17:21:12 · answer #1 · answered by grifter_xiii 2 · 0⤊ 0⤋
sum F_{x} = T_{2} \cos 20 - T_{1} \cos 40 = 0
sum F_{y} = T_{2} \sin 20 + T_{1} \sin 40 - W_{g} = 0
T2 = W/sin20
T1 = w/sin40
This is incorrect. Instead, realize that in order for the man to be in balance, the vertical components of tensions must add up to be equal to the weight.
What is the vertical component of T2? of T1? Then write the condition for vertical equilibrium (which I just stated above
This will give you an equation in terms of T1 and T2. In order to solve for T1 and T2, you'll need another equation. The one for the horizontal components.
2006-09-27 00:19:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's been a while but shouldn't T2Cos40=T1Cos40 if you add T1Cos40 to both sides of the equation? Yea, it's been a while for me.
2006-09-27 00:17:23 · answer #3 · answered by Ron D 4 · 0⤊ 0⤋