a car is driven 125km west and then 65km southwest. what is the displacement of the car from the point of origin?
2006-09-26 16:07:38 · 7 answers · asked by sweethyedreamer213 3 in Education & Reference ➔ Homework Help
i know the answer, i need to know how to do it
2006-09-26 16:10:47 · update #1
the answer is 177km and it is not a right triangle, if it was then yes, that would be trig.
2006-09-26 16:14:32 · update #2
ok here is the exact answer, 177km, 15degrees South of West
2006-09-26 16:19:20 · update #3
thnx u guys especially "person" that really did help.
2006-09-26 16:24:49 · update #4
You draw out what you know, then you can draw imaginary lines to make a right triangle (I wish i could show you) Draw your first to lines, label them, then draw the third line that connects the triangle. Take point A (where you started before you went west) and go straight down, then over to where your sw line connects with your third line. The right triangle you just made will be very helpful because now your problem is trig. The angle of the first 2 lines is 135 degrees.
Hope this helps.
2006-09-26 16:23:12 · answer #1 · answered by person 3 · 0⤊ 0⤋
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2016-11-24 21:31:08 · answer #2 · answered by ? 4 · 0⤊ 0⤋
That's not physics, it's trigonometry.
Compute the size of the legs of an isosceles right triangle with a hypotenuse of 65 km. Then add the distance of one of those legs to 125 km to get the long leg of another scalene right triangle. Compute the hypotenuse of that resulting triangle. Easy as pi!
2006-09-26 16:13:15 · answer #3 · answered by Ralfcoder 7 · 0⤊ 0⤋
D1=125 kmat 180°
2 D =65 km at 225°
The displacement of the car is 177 km at 195°.
AOB 180 45
135
= °−
= °
°
( )( )
( )( )
( ) ( ) ( )( )
2 2 2
2 2
2 2
OB OA AB 2 OA AB cosOAB
OB OA AB 2 OA AB cosOAB
125 km 65 km 2 125 km 65 km cos135
177.03 km
177 km
= + −
= + −
= + −
=
≈
°
( )
1
1
AB OB
sinAOB sinOAB
sinAOB ABsinOAB
OB
AOB sin ABsinOAB
OB
65 km sin135
sin
177.03 km
15.05
−
−
=
=
⎛ ⎞
= ⎜⎜ ⎟⎟
⎝ ⎠
⎡ °⎤
= ⎢ ⎥
⎣ ⎦
= °
180 15.05
195.05
195
θ = ° + °
= °
≈ °
2006-09-26 16:17:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I think this is how u do it
Its to find the hypotenuse of the triangle
125 squared=15625
65 squared=4225
15625+4225=18950
square root of 18950 about 140
its about 140km
2006-09-26 16:11:58 · answer #5 · answered by yellowskinnedguy 3 · 0⤊ 0⤋
one min plz
2006-09-26 16:10:03 · answer #6 · answered by Steve-Ohhhh 2 · 0⤊ 0⤋
190km
2006-09-26 16:10:00 · answer #7 · answered by tommy052588 2 · 0⤊ 0⤋