2006-09-26 14:39:30 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
You would take 100.0 grams of Iron divided by the molar mass (55.845g) to get the number of moles. Then multiply that number by Avagadro's number (6.02214199x10^23) to figure out the number of atoms of Fe you have. The answer happens to be 1.078x10^24 atoms of Iron (Fe)
2006-09-26 14:44:09 · answer #1 · answered by runnerboy516 2 · 0⤊ 0⤋
the molar mass of iron is 55.85 grams/mole
100.0 g X 1 mole/55.85 grams =1.790 moles
There are 6.022 X 10^23 atoms/mole
so # of atoms = 1.790 x6.022x10^23
2006-09-26 21:44:49 · answer #2 · answered by Greg G 5 · 0⤊ 1⤋
what is this
iron has a molar mass of 55.845 g/mol
avagadros # is 6.022 x 10^23
so 100/55.845 * 6.022 x 10^23
is
1.07834184 Ã 10^24
or
1 078 341 840 000 000 000 000 000
or about 1.078 yotta of Iron atoms
2006-09-26 21:56:06 · answer #3 · answered by intracircumcordei 4 · 0⤊ 1⤋