What are the three consecutive integers?

Question

What are the three consecutive odd integers such that three times the first plus four times the second minus the third is 202.

Answer 1

Let the first odd integer be X

The next two consecutive odd integers are therefore

(X + 2) and (X + 4)

Hence,

3X + 4(X+2) - (X+4) = 202

Expanding,

3X + 4X + 8 - X - 4 = 202

6X + 4 = 202

6X = 202 - 4

6X = 198

X = 198/6

X = 33

Therefore the three consecutive integers are:

33, 35 & 37

Answer 2

I would have done it slightly differently.

Since the problem specified odd integers as solutions, I would have used the following, since an odd integer can be written in the form 2*n+1 where n is an integer:

3*(2n+1) + 4*(2n+3) - (2n+5) = 202
(6*n+8*n-2*n) +(3+12-5) = 202
12*n +10 = 202
12*n = 192
n = 16

so the 3 integers are (2*16+1), (2*16+3), (2*16+5) or
33, 35, 37.

Had n not been an integer, then there would have been no odd integer solutions.

Answer 3

A. the three consecutive integers will be written as x, (x+a million), and (x+2). B. You requested the sum. So, it should be further. x + (x+a million) + (x+2) = 36 C. x + (x+a million) + (x+2) = 36 x + x + a million + x + 2 = 36 3x + 3 = 36 3x = 36 - 3 3x = 33 x = 11 We already comprehend that x is 11, so (x+a million) will be 12, and (x+2) will be 13. So the three integers are 11, 12, and 13. wish this helped :)

Answer 4

The formula would be 3x + 4(x+2) - (x+4) = 202.

That would reduce to

3x + 4x + 8 - x - 4 = 202
6x + 4 = 202
6x = 198
x = 198/6 = 33
so the subsequent values would be 35 and 37.

Answer 5

if you assume n to be the first number, the second is n+2, and the third is n+4.
writing your statement in symbolic form:
3n+4*(n+2)-(n+4)=202
expanding:
3n+4n+4*2-n-4=202
regrouping and reducing:
3n+4n-n+8-4=202
7n-n+4=202
6n+4=202
subtract four from each side
6n=198
divide both sides by 6
n=33
so the numbers n, n+2, and n+4 are 33, 33+2, 33+4 or 33, 35, and 37

Answer 6

first you make the smallest integer x. the next one is X+2, then the biggest is X+4. You put those into an equation:

3(x) + 4 (x+2) - (x+4) = 202

Then simplify the equation.

the answer: 33, 35, 37

Answer 7

3x + 4(x + 2) - (x + 4) = 202
3x + 4x + 8 - x - 4 = 202
6x + 4 = 202
6x = 198
x = 33

ANS : 33, 35, and 37

Answer 8

the sum of the first, twice the second, and three times the third

Answer 9

This is the type of cute homework that I despise teachers for assigning.

Nothing is learned ....just a waste of time!

Answer 10

33,35,37
I used an excel spreadsheet to guess and check.