Freckles are dominant over no freckles. Both a Man and a Woman are heterozygous for freckles. Predict the Genotype and Phenotype
2006-09-26 13:42:09 · 4 answers · asked by Kurt 3 in Science & Mathematics ➔ Biology
If they are both heterozygous the chance of freckles is 3 in 4 and the chance of no freckles is 1 in 4.
Here are the genotypes and phenotypes where F represents freckles and f represent no freckles
these are the four possiblities:
FF - will have freckles
Ff - will have freckles
fF - will have freckles
ff- will not have freckles
2006-09-26 13:46:23 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Those answers are correct for the theory. In practice as anyone with freckles can tell you the trait demonstrates incomplete dominance and individuals who are FF have more freckles than those who are Ff.
2006-09-26 14:43:10 · answer #2 · answered by noone 1 · 1⤊ 0⤋
Let F be freckles
and f be no-freckles
F is dominant over f
Father is Ff (you have a pair of the genes - one from your dad and one from your mom)
Mother is Ff also
Genotype. Both will contribute one gene to the sperm (or egg) and so baby can be:
FF (25% of time)
Ff (25% of time)
fF (25% of time)
ff (25% of time)
Note that Ff and fF are essentially the same thing
Phenotype
25% will be homozygotes with freckles
50% will be heterozygotes with freckles
25% will be homozygotes with no freckles
2006-09-26 13:46:49 · answer #3 · answered by Orinoco 7 · 2⤊ 0⤋
ok , its 1/4
hetero means one of each for each so a 1 in 4 chance for phenotype
The genotype goes 1/4 RR , 1/2 Rr Rr, 1/4 rr
2006-09-26 14:01:45 · answer #4 · answered by agropelter 3 · 0⤊ 0⤋