How would you do this Algebra 2 Elimanation method problem?

Question

Say you have a problem like..

3x+2=y
2x+11y=3

Now i know you need to get the variables lined up in order to do that. Now would it be just the same thing like switching the variables and keeping the signs? or would you be changing the sings.. This is what i did.. let me know if im right.

3x+y=2
2x+11y=3

Or would it be something like...

3x-y=-2
2x+11y=3


Let me know.. not looking for what x and y equal.. Just how you would start out to solve it.

Answer 1

Umm the second one is right

So you get the x's and the y's in the right side of things and you want to eliminate one

You could multiply the first line by 11 and then add them both together

(1) 33x - 11y = -22
(2) 2x + 11y = 3

(1) + (2)
35x = -19

and now you have X you can go back and put it back in to find y



Another way to do it would be to multiply the first line by -2 and then multiply the second line by 3 and then you would be able to eliminate the x's

3x -y = -2 (1)
2x +11y = 3 (2)


-6x + 2y = 4 (1) X -2
6x + 33y = 9 (2) X 3

Then add

35y = 13

Solve for y, stick it back in to the equations and solve for x

Answer 2

3x + 2 = y
set to 0
3x-y + 2 = 0
2x + 11y = 3
same
2x + 11y - 3 = 0
subtract [2x + 11y -3] from [3x - y + 2]
x -12y -5 = 0 12y = x-5 solve for y and then replace 5 in above and solve for x

Answer 3

3x + 2 = y
2x + 11y = 3

becomes

3x - y = -2
2x + 11y = 3

Multiply top by 11

33x - 11y = -22
2x + 11y = 3

35x = -19
x = (-19/35)

ANS : (-19/35)

Answer 4

3x-y=-2
2x+11y=3

not sure how to do the rest, I can't really remember. And this seems like early Algebra 1.

Answer 5

Did you consider looking in the textbook. There is probably an illustration a few pages back. Remember the basic laws do not change. You can swap around the additions and subtractions. You can do the same thing to both sides of the equation.

Answer 6

eliminating approach, also conventional as Addition/Subtraction approach. Equation a million: 2x-3y = -3 Equation 2: 5x-2y = -2 Multiply Equation a million through (5) ---> 10x-15y = -15 Multiply Equation 2 through (2) ---> 10x - 4y = -4 -____________ Subtract Equation a million -11y = -11 from Equation 2 clean up for y ----> y = a million Plug in y-value = a million into both equation. ---> 5x-2y = -2 ----> 5x-(2*a million) = -2 ---> 5x = 0 ---> x = 0 accordingly, X = 0 and Y = a million is the answer to this problem. it really is likewise the intersection of both one in each of those lines. SUBSTITUTION approach: Equation a million: y= 8-x Equation 2: 2x+y = 18 For substitution you'll commonly clean up for one variable in a unmarried equation, and then plug it in to the 2d equation (on condition that you only have 2 unknowns). So we are already on condition that (y= 8-x) in equation a million. So we plug that Y-value into equation to to get: -----> 2x+(8-x) = 18 ----> x+8 = 18 ----> x = 10 for this reason plugging 10 into both equation we get carry of that Y= (-2) on your very last question i'm uncertain at that you mean once you assert "3x=4y=14" yet judging out of your previous issues i will anticipate you meant "3x+4y = 14" Equation a million: 3x+4y = 14 Equation 2: x + y = 0 -----> clean up for y ---> y = 0-x or y = -x Plugging in our Y value into equation a million: --> 3x + 4(-x) = 14 clean up for X ---> -x = 14 ---> x = -14 Plug x-value into both equation & clean up for Y ---> -14 + y = 0 ---> Y = 14 accordingly X = -14, and Y=14 is the answer to this (if of route you probably did mean 3x+4y=14)* wish this enables.

Answer 7

stay calm. take a deep breath. now, go to hotmath.com. click login. do not type in a username but type in the password: ac1790ca
once you have logged in click the area that says algebra 2. then find the algebra 2 math book that is the one you have. Then type in the page number, click the problem number and, it will not only give you the answer, but it also gives a step by step synopsis on how to do it.

Answer 8

3x-y=-2
2x+11y=3
this two are right!!!!!!!!!!!!!!!