a) 0.0200 mole AL and 0.0600 mole Cl
b) 0.0800 mole Ba, 0.0800 mole S, and 0.320 mole O
It would be nice if tell me some tips to write this kind formula.
2006-09-26 13:29:42 · 3 answers · asked by hetrp 1 in Science & Mathematics ➔ Chemistry
The key is to divide the smaller number into the larger to get some whole numbers to create empirical formulas from..
So with Al and Cl, divide the 0.02 into the 0.6 and you get a 1 to 3 ratio. So the empirical formula is AlCl3.
With Ba, S, and O, it is clear from division that for every atom of Ba there is one S and four O. So the empirical formula is BaSO4.
2006-09-26 13:48:30 · answer #1 · answered by Alan Turing 5 · 1⤊ 2⤋
a) three times as much Cl as Al, the formula is:
AlCl3
b) Same amount of Ba and S, but four times as much O:
BaSO4
get it?
.0600 moles Cl / .0200 moles Al = 3
.0800 moles Ba / .0800 moles S = 1
.3200 moles O / .0800 moles Ba or S = 4
2006-09-26 13:39:22 · answer #2 · answered by Richard 7 · 5⤊ 0⤋
look in your textbook instead of on yahoo
2006-09-26 13:32:04 · answer #3 · answered by Anonymous · 1⤊ 3⤋