science question help. its about the bohr model of an atom?

Question

i have to draw a picture of an atom. like a "+" for protons, "O" for neutron, and "e-" for electrions. i have to draw a bohr model for "S (2-)" which is Sulfur and has 16 protons. what does the (2-) mean? and what should my drawing have? example= 4 protons, 4 neutrons, 2 electrons.

heres an example picture of what im suppose to draw if you dont get it.

http://i33.photobucket.com/albums/d52/lbabyxchas/helium.jpg

thanks.

Answer 1

2- means two electrons more than protons.

Look up the atomic weight of sulphur. That's the protons plus the neutrons. Both are in the nucleus. There are 16 protons.

There are 18 electrons. Arrange them in the shells (2, then 6, then 10).

Answer 2

Indeed the above answer is correct'ish'. In a perfect would electrons would equal protons and there would be no charge (thus the atom would b e nuetral). However, all atoms (except Nobel Gases) gain or lose electrons. Sulfur will gain two thus have the unbalance charges making it -2. This is why it forms compounds with other positive elements to get back to zero.

So, if you are just doing Sulfur draw it with 16 p and 16 e. If you are drawing sulfur -2 draw it with 16 p and 18 e.

Fun, huh!!

Answer 3

truthfully the above answer is real'ish'. In a suitable would favor to electrons would favor to equivalent protons and there would favor to be no value (for this reason the atom would favor to b e nuetral). as well the easy shown reality that, all atoms (except Nobel Gases) income or lose electrons. Sulfur will income 2 for this reason have the unbalance expenditures making it -2. it really is the reason it varieties compounds with diverse smart elements to come back to 0. So, if you're in straightforward words doing Sulfur draw it with 16 p and 16 e. if you're drawing sulfur -2 draw it with 16 p and 18 e. exciting, huh!!