plz i need help fast!?

Question

PLZ I NEED TO FINISH IT ASAP!
this is the problem 3{[9(x-2)+7]-2[4(x+5)-36]}?

Answer 1

3{[9(x-2)+7]-2[4(x+5)-36]}?

break it down
9(x-2)+7
9x-18+7
9x-11

4(x+5)-36
4x+20-36
4x-16

3((9x-11)-2(4x-16))
3(9x-11-8x+32)
3(9x-11-8x+32)
3(x+21)
3x-63

I AM CORRECT

Note: there are alot of wrong answers posted below me, but you can TEST this one and it works!
I'll show you:
Let's substitute 4 in for X
3((9(4-2)+7)-2(4(4+5)-36))
3((9(2)+7)-2(4(9)-36))
3((18+7)-2(36-36))
3(18+7-2(0))
3(18+7)
3(25)
75

3(4)+63
12+63
75

See? It works!

Answer 2

I'm not sure if this is correct. It's been a while since I've done this kind of Math, but I think this is the solution. ( I hope someone more knowledgable then me comes and checks this )
First look at the problem as 3 seperate equations:
9(x-2)+7 and -2[4(x+5)-36] and after doing this you multiply everything by 3, but thats last.
Start with the parenthesis first. Multiply the number outside by whats inside the parenthesis: 9(x-2)+7 and 4(x+5)-36
= 9x-18 and 4x+20
9x-18+7 and 4x+20-36
Then add the numbers without a variable x, together.
-18+7= -11 and +20-36= -16
So you have: 9x-11 and 4x-16
Then do the brackets. Multiply -2 [4x-16].
You get: 8x+32
Theres nothing outside this bracket. [9x-11], so leave it alone for now.
Now do whats in this thingy { }.
Subtract the variables together: 9x-8x= x
And add the numbers: -11+32 =+21
You get: x+21
Now just multiply the 3 by whats in the thingy: 3{x+7}
= 3x+63

This is your final answer ( I think ):
3x+63

Here's this solution written out:
3{ [9(x-2)+7] -2[4(x+5)-36]}
9x-18 +7 4x+20-36
4x-16
-8x+32
9x-11
3 {9x-11-8x+32}
9x-8x= x
-11+32=+21
3{x+7}=
3x+63

Answer 3

Take the equation and start with the inner most parenthesis:
3{[9(x-2)+7]-2[4(x+5)-36]}

distribute:
3[(9x-18+7)-2(4x+20-36)]

combine like terms within the parenthesis:
3[(9x-11)-2(4x-16)]

now do the inner most parenthesis again and distribute:
3(9x-11-8x-32)

combine like terms:
3(x-43)

distribute the 3
3x-129

Answer 4

First, within the parenthesis, distribute the 9 and 4 over the second set of parenthesis:

3{[(9x-18)+2]-2[(4x+5)-36)]}

Then, collect like terms on both sides:

3[(9x-16)-2(4x-31)]

Then, distribute the 2 over the second set of parenthesis:

3[(9x-16)-(8x-62)]

Now, collect like terms within the parenthesis:

3(9x-8x-16+62)=3(9x+46)

Then distribute the three over the last parenthesis:

18x+138.

I think.

Answer 5

First work on the equations inside the brackets.

9(x-2)+7
9x-18+7
9x-25
--------
2[4(x+5)-36]
2[4x+20-36]
2[4x-16]
8x-32
---------

3(9x-25-8x-32)
3(9x-8x-32-25)
3(x-57)
3x-171

Ta-da.

Answer 6

Probably 7

Answer 7

3( 9x -18 + 7) - 2(4x + 20) - 36
3( 9x - 11) - 8x -40 - 36
27x -33 -8x - 40 -36

15x - 109

Answer 8

3{[9x-18+7]-2[4x+20-36]}
3{9x-11-2[4x-16]}
3{9x -11-8x+32}
27x-33-24x+96
3x+63

Answer 9

3[9x-18+7]-2[4x+20-36]
=27x-33-8x+32
21x-1

Answer 10

Aight this is thee right answer. Gosh! U know how long it took me to do this!? [lol] But its all good. I wanted to, cuz im tight like that =P. And i know i got the right answer too.

♥Its....3x -29♥