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Two dice are rolled, oen at a time. Find the probability of rolling a 5 on the first die and a 2 on the second. Round to the nearest percent.
A. 3% <-- what i solved it as.
B 17%
C 33%
D 100%

Refer to the above. Find the probability of rolling both numbers less than 4. Round to the nearest whole percent.
A 13%
B 25%
c 50%
d 75%

Hopefully this is my last question about probability for today.

2006-09-26 11:48:44 · 7 answers · asked by Madcat 2 in Science & Mathematics Mathematics

7 answers

first, u ought to consider all possible outcomes.
all possible outcomes are- (1,1) , (1,2),..... (1,6)
- (2,1) (2,2) ,......(2,6)
- (3,1) (3,2),......(3,6)
- (4,1) , (4,2) ,....(4,6)
- (5,1) , (5,2) ,..... (5,6)
- (6,1 ) ,(6,2), .........., (6,6)

so, all possible outcomes are 36.


for the first part, P ( rolling 5 on first die and 2 on second) =

P (rolling 5 on first) x P (rolling 2 on second)

6/36 x 6/36

1/36

if u change 1/36 into percentage form, 1/36 x 100 = 100/36 = 2.8% approximately equal to 3%


for the second part, the favourable outcomes are 9.

which are (1,1) , (1,2) ,(1,3), (2,1) ,(2,2) ,(2,3) , (3,1) ,(3,2) , (3,3)

probability is 9/36 = 1/4

1/4 is equal to 25%

2006-09-26 21:25:33 · answer #1 · answered by free aung san su kyi forthwith 2 · 1 0

looks like you got the first one correct

the second one is similar

First you have to decide what are the odds of rolling a number less than 4. That is, a 1, a 2, or a 3. Since there are six possible outcomes, the chance of rolling 1,2, or 3 (3 choices) is .5 (3 out of 6)

so, the chance of the first roll being under 4 is .5
and the chance of both being under 4 is .5*.5=.25
or, 25%

what do you think? look right to you?

2006-09-26 18:54:18 · answer #2 · answered by enginerd 6 · 2 0

First question:
The probability of rolling a 5 on the first one is 1/6 and the probability of rolling a 2 on the second one is 1/6 too. Thus, the probability of happening both of them together, is: 1/6 x 1/6 = 1/36 ≈ 0.0277 ≈ 0.03 or 3%

Second question:
The probability of rolling the first one less than 4(1,2 or 3), is 3/6 which is equal to 1/2. Its the same for the second one. Therefore, the probability of happening both of them together, is: 1/2 x 1/2 = 1/4 = 0.25 or 25%

2006-09-26 19:04:42 · answer #3 · answered by Arash 3 · 1 0

Your odds of rolling a single die and getting a number less than 4 is 50% - you can roll a 1, 2 or 3. Your odds of doing this twice are 50% * 50%, or 25%.

2006-09-26 18:54:45 · answer #4 · answered by astazangasta 5 · 0 0

number one
each time you role a die you have a 1 in 6 chance to get the number you want. there fore you have a 1/6 or 17% chance

Number 2

You are looking for three possible numbers in this problem 1,2,3. so 3/6 or 50%

2006-09-26 18:58:36 · answer #5 · answered by Richmond C 3 · 0 0

Your first part is right
second is 25%=0.5*0.5=0.25

2006-09-26 18:54:46 · answer #6 · answered by Amar Soni 7 · 1 0

I'd say 13% Good Luck ! :)

2006-09-26 18:51:14 · answer #7 · answered by tysavage2001 6 · 0 0

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