2006-09-26 11:19:38 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
i think it's 1/2 ln(3x^2 + 8x + 1) + c
this is because the diffrential of the denominator is 2(3x+4) and so we can say the integral of 1/2f'(x)/f(x) = lnf(x)
the integral of 1/f(x) = 1/f'(x) lnf(x) + c :. the integral of1/2f'(x)/f(x) is (1/2f'(x))/f'(x) lnf(x) + c
can you see?
2006-09-26 11:23:30 · answer #1 · answered by Anonymous · 0⤊ 1⤋
-1 & 1
2006-09-26 18:27:27 · answer #2 · answered by lal 2 · 0⤊ 1⤋
1235
2006-09-26 18:20:53 · answer #3 · answered by jahjahbinks 2 · 0⤊ 1⤋
put x^2=t
the equation becomes a Q.E.
3t^2-8t+5=0
3t^2-3t-5t+5=0
3t(t-1)-5(t-1)=0
(t-1)(3t-5)=0
t=1 or 5
reverting back to x^2
x^2=1 so x=+/-1
x^2=5 x=+/-rt5
the four roots are 1,-1,rt5,-rt5
2006-09-26 18:26:07 · answer #4 · answered by raj 7 · 0⤊ 1⤋
+-1 and +-sqrt(15 )/3
2006-09-27 02:12:22 · answer #5 · answered by Mamad 3 · 0⤊ 0⤋
x= (1/3)*(15)^(.5),-(1/3)*(15)^(.5),
1, & -1
or X= 1.29, -1.29, 1, -1
2006-09-26 18:33:02 · answer #6 · answered by nano2ndd 2 · 0⤊ 1⤋