Answers could be
1. 6 to 2
2. 2 to 6
3. 8 to 4
4. 6 to 6
When i do it i always come up with 8 to 12.. but its not one obviously
2006-09-26 10:57:06 · 8 answers · asked by Madcat 2 in Science & Mathematics ➔ Mathematics
Thank you.
2006-09-26 11:08:14 · update #1
odds are always for:against and so in this case
8:4
2006-09-26 11:01:00 · answer #1 · answered by vnav_in 2 · 1⤊ 0⤋
3. 8 to 4
2006-09-26 18:13:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4
2006-09-26 18:04:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The odds of choosing a red OR white chips is equal to odds of choosing a red chip plus the odds of choosing a white chip. The probability of choosing a red chip is 1/2. The probability of choosing a white chip is 1/6. The probability of choosing a red or white chip is thus 2/3. The odds are then 2:1 or 8:4
2006-09-26 18:01:00 · answer #4 · answered by Greg G 5 · 0⤊ 0⤋
red or white is 8 out of 12 since their are 6 reds and 2 whites and the total is 12.
2006-09-26 18:00:43 · answer #5 · answered by t_nguyen62791 3 · 0⤊ 0⤋
the probability is 8 in 12 but the odds are 8 to 4.
You had the right answer but the wrong terminology.
2006-09-26 18:13:43 · answer #6 · answered by Joe C 3 · 1⤊ 0⤋
8:4
[6(red)+2(white)]/12(all)=8:12 this is the probability
1-8:12=4:12
so odd=(8:12)/(4:12)=8:4
2006-09-27 05:47:28 · answer #7 · answered by farsh m 1 · 0⤊ 0⤋
(6+2)/12 = 8/12
for 8 : against 4 (answer 3)
2006-09-26 18:41:17 · answer #8 · answered by Anonymous · 0⤊ 0⤋