In order to earn an A in a course, a 85% average is needed. There are 4 regular tests, and a final exam which is weighted twice as much as a regular test. If the test scores are 95%, 79%, 89% and 97%, what is the lowest final exam % score that will result in a final grade of A?
I got to the point where 16 2/3% is the weight of the regular test and 33 1/3% would be the weight of the final exam, but im not sure how to set up an equation from there... thanks for the help
2006-09-26 09:50:35 · 11 answers · asked by NOooob! 1 in Science & Mathematics ➔ Mathematics
Each 4 exam counts for 1/6 of the score, and the final for 2/6 (soince 4* 1/6 + 2/6 is 6/6).
So you can divide each of the score by 6 (95+79+89+97)/6 = 60,
leaving you with a (85-60)= 25 points to get.
This 25 point must be the result of the required score divided by 3 (or multiplied by 2 and divided by 6), so the final score required is 75%.
2006-09-26 09:57:46 · answer #1 · answered by Vincent G 7 · 0⤊ 0⤋
add the test scores up which is 95 + 79 + 89 + 97 which gives you 360
multiply 6 (# of tests + 2 for the final exam) by 85 which gives you 510
subtract 510-360 = 150
divide 150 by 2 and get 75%
thats what you have to get on the final exam
equation is 97+79+95+89+2x = 6*85
2006-09-26 09:54:30 · answer #2 · answered by angel1219us 2 · 0⤊ 0⤋
(The sum of those 4 tests)/6 + (the final)/3 = 85%
so, (.95+.79+.89+.97)/6 + x/3 = .85
solve for x
2006-09-26 09:56:03 · answer #3 · answered by CaptainObvious 3 · 0⤊ 0⤋
(95+79+89+97+2*x)/6 >= 85
(360 + 2*x) / 6 >= 85
60 + x/3 >= 85
x >= 3 * (85 - 60) = 75
2006-09-26 10:21:16 · answer #4 · answered by Joe C 3 · 0⤊ 0⤋
95+79+89+97+2x=(6*85)
2x=510-360=150
so 75% in the final exam is the answer
-
2006-09-26 09:57:27 · answer #5 · answered by raj 7 · 0⤊ 0⤋
Effectively you are saying
(95 + 79 + 89 + 97 +2x)/6 = 85
Hence x = 75% minimum
2006-09-26 09:54:22 · answer #6 · answered by ? 7 · 0⤊ 0⤋
1 regular test = x 1 final exam = 2x
4 regular tests = 4x ; 4x + 2x = 6x = total points possible
The average of the four tests is 90%.
.9 X 4x = 3.6x; .85 X 6x = 5.1x -- this is minimum points req'd for an "A"; 5.1x - 3.6x = 1.5x -- this is the no. of points req'd on the final exam to earn an "A". 1.5x/2x = 75% required on final.
Equation : (85% X 6x) - (90% X 4x)/2x = 5.1x - 3.6x/2x = 75%
2006-09-26 12:32:49 · answer #7 · answered by THE ENCYCLOPEDIA 1 · 0⤊ 0⤋
You can get a 75% on the final and still get a final grade of 85%.
2006-09-26 09:56:15 · answer #8 · answered by snowboarder878 1 · 0⤊ 0⤋
85% is an A? in what school?
2006-09-26 10:04:57 · answer #9 · answered by Anonymous · 0⤊ 0⤋
a hundred+one hundred fifty+20+one hundred ten=380 till the a hundred that examine a and one hundred fifty that examine b incorporates the 20 that examine the two, wherein case you will possibly take 20 from each, that's comparable to takin away 40, and 380-40=340
2016-10-01 09:43:12 · answer #10 · answered by bungay 4 · 0⤊ 0⤋