An unknown metal with a mass of 28g absorbs 58 J of heat. Its temp rises from 31.1 *C to 39.9*C. Calculate the heat capacity of the metal. Please let me know how you are doing this, and if there are any short cuts using a TI-89 titanium calculater. Thanks
2006-09-26 07:51:45 · 5 answers · asked by Angel Eve 6 in Science & Mathematics ➔ Chemistry
Specific heat and heat capacity are the same thing.
Heat = Sp. H. * mass * (delta)T
Sp. H. = Heat/(mass * (delta)T) = 58J/ (28g * 8.8C)
Sp. H. = 0.236 J/g C
2006-09-26 08:02:49 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
heat capacity is the ammount of heat (energy) it takes to to raise one gram of a material one degree.
dQ = m C dT
or change in enengy = mass * heat capacity * change in temp
or C = dQ/(m dT)
here your change in energy is 58 joules, your mass is 28 g and your change in temp is 8.8 degrees
so C = 58/(28*8.8)
I guess you could use the calculator to do that math... but that is the only trick to it. (just know what the equation means)
2006-09-26 08:01:25 · answer #2 · answered by farrell_stu 4 · 2⤊ 0⤋
looking at your picture you dont need any help with your chemistry
2006-09-26 08:00:35 · answer #3 · answered by Edward B 4 · 0⤊ 3⤋
ummm.......with that picture of yours I help you with anything you want;)
2006-09-26 07:54:19 · answer #4 · answered by Anonymous · 0⤊ 3⤋
only if you take your top off.
2006-09-26 07:54:06 · answer #5 · answered by Mark D 3 · 0⤊ 4⤋