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i had this question
work out the nth term for this sequence
0,0,12,24,36,48
the answer is - 12(n-2)

what would the answer be for these sequences?
1.0,0,6,24,54
2.0,8,8,8,8,
3.0,0,1,10,27,64

2006-09-26 07:35:11 · 2 answers · asked by Alice K 4 in Education & Reference Homework Help

12X(n-2)

2006-09-26 07:41:52 · update #1

12X(n-2)

2006-09-26 07:41:53 · update #2

2 answers

12n(n-2) does not give you 0,0, etc. The correct answer for the first question that you answered is 6n(n-1).

1. I see 6 * 0^0, then 6 * 2^2 and then 6 * 3^3...so 6 * n^n, but that only works for the first 0...not two 0s. Maybe it will help you.

I am trying to figure it out...haven't done it in a while.

2006-09-26 08:28:21 · answer #1 · answered by paisak79 3 · 0 0

0,0,12,24,36,48

being a0-0, a1-0, a2-12,a3-32...an-? We know starting at n >= 2 we have a common difference of 12 therefore a(n)= 0 + (n-1)*12 where n >= 2 given a(0)=a(1)=0. Looking at 12(n-2) needs a condition if not it fails the sequence, 12(0-2) = -24 not 0 for a(0) and 12(1-2) = -12 not 0 for a(1)...my basis that it appears as an arithmetic sequence

1) a(n) = (n-1)(n-1)(6) where a(0)=0 and n>=1
pattern: a(0) = 0 a(1) = 0, a(2)=6 a(3)=24..
how i viewed it:
a(2) = 3*2
a(3) = (2*2)(3*2)
a(4) = (3*3)(3*2)...where (3*2) or 6 is common

2) a(0) = 0, a(n) = 8 where n>=1 guessed

2006-09-26 08:21:02 · answer #2 · answered by Arkane Steelblade 4 · 0 0

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