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K[Co(C2O4)2(H20)2] all of the numbers are lower case

[Fe(NH3)2(NO2)2]2SO4 all of the numbers are lower case

2006-09-26 04:59:46 · 3 answers · asked by nedjine05 1 in Science & Mathematics Chemistry

3 answers

The basic procedure for naming a complex:

1. When naming a complex ion, the ligands are named before the metal ion.
2. Write the names of the ligands in alphabetical order. (Numerical prefixes do not affect the order.)
* Multiply occurring monodentate ligands receive a prefix according to the number of occurrences: di-, tri-, tetra-, penta-, or hexa. Polydentate ligands (e.g., ethylenediamine, oxalate) receive bis-, tris-, tetrakis-, etc.
* Anions end in o. This replaces the final 'e' when the anion ends with '-ate', e.g. sulfate becomes sulfato. It replaces 'ide': cyanide becomes cyano.
* Neutral ligands are given their usual name, with some exceptions: NH3 becomes ammine; H2O becomes aqua; CO becomes carbonyl; NO becomes nitrosyl.
3. Write the name of the central atom/ion. If the complex is an anion, the central atom's name will end in -ate, and its Latin name will be used if available (except for mercury).
4. If the central atom's oxidation state needs to be specified (when it is one of several possible, or zero), write it as a Roman numeral (or 0) in parentheses.
5. Name cation then anion as separate words (if applicable, as in last example)

Examples:

[NiCl4]2- → tetrachloronickelate(II) ion
[CuNH3Cl5]3- → amminepentachlorocuprate(II) ion
[Cd(en)2(CN)2] → dicyanobis(ethylenediamine)cadmium(II)
[Co(NH3)5Cl]SO4 → pentaamminechlorocobalt(III) sulfate

In this case,
potassium diaquabis(oxalato)cobaltate
diamminedinitritoiron(III) sulfate

2006-09-26 06:52:52 · answer #1 · answered by Mr. E 5 · 0 0

Potassium bisaqua bisoxallo cobaltate (III)

The second compound appears to be science fiction.

2006-09-26 12:18:04 · answer #2 · answered by Richard 7 · 0 0

Second one is diamminodinitroiron(III) sulfate.

2006-09-26 13:33:22 · answer #3 · answered by TheOnlyBeldin 7 · 0 0

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