6*x^3 = 5*x - 7 is what is called a "depressed cubic" since it has no x^2 term.
Rearrange terms and transform the above equation to,
x^3 - 5/6*x = -7/6
so A = -5/6 and B = -7/6, and the solution is outlined here:
http://www.sosmath.com/algebra/factor/fac11/fac11.html
(If it weren't a "depressed" cubic, but a regular cubic, there is a way to get it into depressed cubic form.)
2006-09-26 04:47:57
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answer #1
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answered by Joe C 3
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6x =18
5x5=25 - 7=18
2006-09-26 10:06:43
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answer #2
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answered by nas88car300 7
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Till now, I only know about squared. Not cubed. Sorry ^2
2006-09-26 10:04:03
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answer #3
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answered by Bilal Hares 3
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6 * x^3 intersects the line 5 * x - 7 when x = -1.312
2006-09-26 10:26:47
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answer #4
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answered by Anonymous
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2:
2006-09-26 10:06:56
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answer #5
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answered by screams without lungs 2
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You're better off taking your teacher out for a couple of drinks, and trying to strike up a deal. But, before you do that, are upir SURE you want to know the answer
2006-09-26 10:02:42
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answer #6
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answered by clear_skyzz 2
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35\6
2006-09-26 10:01:02
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answer #7
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answered by ghada.abassy 1
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DONT KNOW HOW TO DO IT ON COMPUTER OTHER WISE ITS EASY,
take 5x to left,...and so on
2006-09-26 10:02:05
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answer #8
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answered by alok n 2
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sorry, can't help.. that's astronomical
2006-09-26 10:00:29
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answer #9
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answered by Mr. Owl 3
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5.4
2006-09-26 10:01:00
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answer #10
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answered by jasminenlady07 2
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