the formula for centripetal that i have learn is a=v^2/r...if i derive the the motion formula..v^2=u^2+2as...where a is acceleration and s is displacement ..i get the centripetal force is...a=v^2/2r.........where the 1/2 go?
2006-09-24 20:42:21 · 4 answers · asked by pouli 2 in Science & Mathematics ➔ Physics
The formula v^2=u^2+2as is applicable to linear motion, while the one you gave concerning centripetal force is about circular motion. Your question "where the 1/2 go?" is not clear.
2006-09-25 05:41:54 · answer #1 · answered by tul b 3 · 0⤊ 0⤋
How did you derive this? In circular motion, the acceleration is perpendicular to the velocity.
v^2 = u^2 + 2as, there acceleration component in direction of velocity is considered and it increases the magnitude of the velocity.
In circular motion, the centripetal acceleration does not change the magnitude of velocity, it only changes the direction. It has no component in the direction of the velocity.
2006-09-24 20:48:17 · answer #2 · answered by astrokid 4 · 1⤊ 0⤋
Centripetal acceleration is what prevents the earth from falling into the sun. That doesn't really answer your question but I thought it was neat.
2006-09-24 20:45:46 · answer #3 · answered by Julian 6 · 0⤊ 2⤋
Constant of integration.
retry in reverse to derive the equation. If need to ask again, show every step.
2006-09-24 20:54:59 · answer #4 · answered by Anonymous · 0⤊ 1⤋