ln(1-e^-x)?

Question

Is there a way to simplify ln(1-e^-x) further if I want to solve for x?

Answer 1

ln(1-e^-x) = ln (1/1-e^x)= ln 1 - ln( 1-e^x)=
ln 1 + ln 1/ ln ( e^x) = 0 ( No matter what x is , because ln 1 is 0 )