At the local Sunday School, the teacher brought in some puppies. There were
20 more children than puppies. In the corner of the room, the teacher had
an ant's nest. In the nest were exactly 10 times more ants than children.
In total, including the teacher, the children, the puppies and the
ants,there were 1440 legs in the room.
2006-09-24 18:12:06 · 7 answers · asked by Jeffrey Z 1 in Science & Mathematics ➔ Mathematics
first,we let x= no. of children
so puppies=x-20
ants=10x
children have 2 legs=2x
puppies have 4 legs=4(x-20)
ants have 6 legs=60x
teacher has 2 legs=2
so 2x+4(x-20)+60x+2=1440
x=23
so there are 23 children
anyway the question should say 10 times AS MUCH ants as children and not 10 times MORE than children
2006-09-24 18:28:28 · answer #1 · answered by dark gorilla 1 · 0⤊ 0⤋
Children have two legs
Puppies have 4 legs
Ants have 6 legs
So 6*Ants + 4*Puppies +2*Children + 2*T= 1440
A = 10C
C = P+20
T = 1
So A = 10(P+20)
6*(10(P+20)) + 4*P + 2(P+20) + 2T = 1440
60P+ 1200 +4P +2P +40 +2 = 1440
66P +1242 = 1440
66P = 198
P = 3
3 Puppies, 23 children, 1 teacher, 230 ants
3 *4 + 23*2 + 2 + 1380
12+ 46 + 2 + 1380 = 1440
2006-09-25 01:31:38 · answer #2 · answered by John T 6 · 0⤊ 0⤋
There are 3 puppies in the room, 23 children, 230 ants.
The legs part works out to be 2 (teacher) + 46 (children) + 12 (puppies) + 1380 (ants) = 1440!
Good luck!
2006-09-25 01:31:41 · answer #3 · answered by wd2crv 3 · 0⤊ 0⤋
33=68 13=52 330=1320
33 children.
33 children +1 teacher = 68 legs
13 puppies = 52 legs
330 ants = 1320 legs
total of 1440 legs
2006-09-25 01:30:46 · answer #4 · answered by GEE-GEE 5 · 0⤊ 0⤋
devide 1440 by 2
2006-09-25 14:32:28 · answer #5 · answered by sharon b 3 · 0⤊ 0⤋
20?
2006-09-25 01:20:17 · answer #6 · answered by xrionx 4 · 0⤊ 0⤋
20students
1 puppy
200 ants
1 teacher
is it incorrect?
2006-09-25 01:35:34 · answer #7 · answered by corrona 3 · 0⤊ 0⤋