There is a question I am not sure exactly what to do for it "For log y= log(0.5x-3) + log 2, State the domain, then express y as a funtion of x."
2006-09-24 18:05:07 · 3 answers · asked by gg 4 in Science & Mathematics ➔ Mathematics
log(y) = log(.5x - 3) + log(2)
log(y) = log(2(.5x - 3))
log(y) = log(x - 6)
y = x - 6
.5x - 3 > 0
.5x > 3
x > 6
Domain :
x > 6
y = x - 6
2006-09-24 18:53:59 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
The domain (set of x values for which this function is defined), assuming that we're only talking about real numbers, is all numbers greater than 6. i.e. x > 6. That's because for x=6 the argument of the log(0.5x-3) is 0 and for x < 6 it's less than 0. log is only defined for arguments greater than zero. Stated concisely, mathematically, the domain is (6, infinity), which is the same as x > 6.
2006-09-24 20:07:00 · answer #2 · answered by pollux 4 · 0⤊ 0⤋
log y = (log 0.5x -3) + log 2
log y = log 2 ( 0.5x - 3) = log (x-6)
y = x-6
2006-09-24 18:09:57 · answer #3 · answered by Confused 4 · 0⤊ 0⤋