1. MnO-4 (aq) + S2O3(aq) => Mn (aq) + SO4 (aq) in acidic solution
2006-09-24 17:30:34 · 3 answers · asked by xoxo_jenn_24 2 in Science & Mathematics ➔ Chemistry
If you insert coefficients of 5, 4, 5, and 8 for the four components, I think the atoms will balance.
However, you should also figure out what happens to the charges.
I think the charges for the four ions are: -1, -2, don't know, and -2.
If you try to solve for the "don't know," it isn't an integer, so I'm not sure how to make the charges balance.
2006-09-24 18:24:36 · answer #1 · answered by actuator 5 · 0⤊ 0⤋
I am rusty (oxidized) on this, but need to review:
But first, are you certain that this is the question, since you have Mn (aq), which is not soluble, maybe you mean Mn++, please clarify.
2006-09-24 17:45:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5MnO4 + 4S2O3 -> 5Mn + 8SO4
2006-09-24 20:47:32 · answer #3 · answered by johnny m 2 · 0⤊ 0⤋