1.899x10exp-4 mol of an unidentified gaseous substance effusesthrough a tiny hole in 81.1s. Under identical conditions, 1.664x10exp-4 mol of argon gas takes 88.5s to effuse.
2006-09-24 16:50:15 · 2 answers · asked by Brain P 1 in Science & Mathematics ➔ Chemistry
the rate at which as gas effuses is in an inverse relationship with the square root of its molar mass; that is, smaller gasses effuse faster...
and since time used in effusion is also in an inverse relationship with rate of effusion; t1/t2 = sq rt (M1/M2)
Argon gas is a noble gas with a uniatomic molecule, thus the atominc weight of Ar = the Molecular weight of argon gas...
do the rest of the calculations arithmatically
2006-09-24 16:54:13 · answer #1 · answered by kb27787 2 · 0⤊ 0⤋
Christ almighty, will you do your own homework?
2006-09-24 16:51:35 · answer #2 · answered by Anonymous · 0⤊ 1⤋